# If a reaction follows the Arrhenius equation,

Question:

If a reaction follows the Arrhenius equation, the plot lnk vs $\frac{1}{(\mathrm{RT})}$ gives straight line with a gradient $(-\mathrm{y})$ unit. The energy required to activate the reactant is:

1. $\mathrm{y} / \mathrm{R}$ unit

2. y unit

3. yR unit

4. - y unit

Correct Option: , 2

Solution:

From Arrhenius equation,

$\mathrm{k}=\mathrm{Ae}^{-\mathrm{E}_{\mathrm{a}} / \mathrm{RT}}$

$\ln k=\ln A-\frac{E_{a}}{R T}$

slope $=-y$ (given)

$-y=-\mathrm{E}_{\mathrm{a}}$

$\Rightarrow \mathrm{E}_{\mathrm{a}}=y$