If ∆ABC ∼ ∆DEF such that 2 AB = DE and BC = 6 cm, find EF.


If ∆ABC ∼ ∆DEF such that 2 AB = DE and BC = 6 cm, find EF.


$\because \triangle A B C \sim \triangle D E F$

$\therefore \frac{A B}{D E}=\frac{B C}{E F}$

$\Rightarrow \frac{1}{2}=\frac{6}{E F}$

$\Rightarrow E F=12 \mathrm{~cm}$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now