If α and β are the zeros of the polynomial


If $\alpha$ and $\beta$ are the zeros of the polynomial $p(x)=2 x^{2}+5 x+k$ satisfying the relation $\alpha^{2}+\beta^{2}+\alpha \beta=\frac{21}{4}$ then find the value of $k$.


Let $\alpha$ and $\beta$ be the zeroes of the polynomial $p(x)=2 x^{2}+5 x+k$.

Sum of zeroes $=-\frac{b}{a}$

$\Rightarrow \alpha+\beta=-\frac{5}{2} \quad \ldots(1)$


Product of zeroes $=\frac{c}{a}$

$\Rightarrow \alpha \beta=\frac{k}{2} \quad \ldots(2)$

Now, using (1)


Squaring both sides, we get


$\Rightarrow \alpha^{2}+\beta^{2}+2 \alpha \beta=\frac{25}{4}$

$\Rightarrow \alpha^{2}+\beta^{2}+\alpha \beta+\alpha \beta=\frac{25}{4}$

$\Rightarrow \frac{21}{4}+\alpha \beta=\frac{25}{4}$

$\Rightarrow \alpha \beta=\frac{25}{4}-\frac{21}{4}$

$\Rightarrow \alpha \beta=1$

$\Rightarrow \frac{k}{2}=1 \quad($ from $(2))$

$\Rightarrow k=2$

Hence, the value of is 2.


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