If bisectors of ∠A and ∠B of a quadrilateral ABCD intersect each other at P, of ∠B and ∠C at Q,


If bisectors of ∠A and ∠B of a quadrilateral ABCD intersect each other at P, of ∠B and ∠C at Q, of ∠C and ∠D at R and of ∠D and ∠A at then PQRS is a
(a) rectangle
(b) parallelogram
(c) rhombus
(d) quadrilateral whose opposite angles are supplementary


Given: In quadrilateral ABCDAS, BQ, Cand DS are angle bisectors of angles A, B, C and D, respectively.

QPS = APB        (Vertically opposite angles)          ...(1)


APB + PAB + ABP = 180°        (Angle sum property of triangle.)

$\Rightarrow \angle A P B+\frac{1}{2} \angle A+\frac{1}{2} \angle B=180^{\circ}$

$\Rightarrow \angle A P B=180^{\circ}-\frac{1}{2}(\angle A+\angle B)$             ...(2)

From (1) and (2), we get

$\angle Q P S=180^{\circ}-\frac{1}{2}(\angle A+\angle B)$             ...(3)

Similarly, $\angle Q R S=180^{\circ}-\frac{1}{2}(\angle C+\angle D)$         ...(4)

From (3) and (4), we get

$\angle Q P S+\angle Q R S=360^{\circ}-\frac{1}{2}(\angle A+\angle B+\angle C+\angle D)$




So, PQRS is a quadrilateral whose opposite angles are supplementary.

Hence, the correct option is (d).




Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now