Question:
If $f: R \rightarrow R, g: R \rightarrow$ are given by $f(x)=(x+1)^{2}$ and $g(x)=x^{2}+1$, then write the value of fog $(-3)$.
Solution:
$(f o g)(-3)=f(g(-3))$
$=f\left((-3)^{2}+1\right)$
$=f(10)$
$=(10+1)^{2}$
$=121$
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