If one of the equation ax2 + bx + c = 0 is three times times the other, then b2 : ac =
(a) 3 : 1
(b) 3 : 16
(c) 16 : 3
(d) 16 : 1
Let $\alpha$ and $\beta$ be the roots of quadratic equation $a x^{2}+b x+c=0$ in such a way that $\alpha=3 \beta$
Here, $a=a, b=b$ and,$c=c$
Then,
according to question sum of the roots
$a+\beta=\frac{-b}{a}$
$3 \beta+\beta=\frac{-b}{a}$
$4 \beta=\frac{-b}{a}$
$\beta=\frac{-b}{4 a} .$.....(1)
And the product of the roots
$\alpha \cdot \beta=\frac{c}{a}$
$3 \beta \times \beta=\frac{c}{a}$
$3 \beta^{2}=\frac{c}{a}$
$\beta^{2}=\frac{c}{3 a} \ldots$(2)
Putting the value of $\beta=\frac{-b}{4 a}$ in equation (2)
$\left(\frac{-b}{4 a}\right)^{2}=\frac{c}{3 a}$
$\frac{b^{2}}{16 a^{2}}=\frac{c}{3 a}$
$b^{2}=\frac{16 a c}{3}$
$\frac{b^{2}}{a c}=\frac{16}{3}$
$b^{2}: a c=16: 3$
Thus, the correct answer is $(c)$
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