Question:
If P(E) = 0.05, then P(not E) =
(a) −0.05
(b) 0.5
(c) 0.9
(d) 0.95
Solution:
Given: $P(E)=0.05$
TO FIND: $P(\bar{E})$
CALCULATION: We know that sum of probability of occurrence of an event and probability of non occurrence of an event is 1. Therefore
$P(E)+P(\bar{E})=1$
$0.05+P(\bar{E})=1$
$P(\bar{E})=1-0.05$
$P(\bar{E})=0.95$
Hence the correct answer is option $(d)$