If $p(x)=5 x-4 x^{2}+3$ then $p(-1)=?$
Question.
If $p(x)=5 x-4 x^{2}+3$ then $p(-1)=?$
(a) 2
(b) –2
(c) 6
(d) –6
If $p(x)=5 x-4 x^{2}+3$ then $p(-1)=?$
(a) 2
(b) –2
(c) 6
(d) –6
Solution:
$p(x)=5 x-4 x^{2}+3$
Putting $x=-1$ in $p(x)$, we get
$p(-1)=5 \times(-1)-4 \times(-1)^{2}+3=-5-4+3=-6$
Hence, the correct answer is option (d).
$p(x)=5 x-4 x^{2}+3$
Putting $x=-1$ in $p(x)$, we get
$p(-1)=5 \times(-1)-4 \times(-1)^{2}+3=-5-4+3=-6$
Hence, the correct answer is option (d).