# If $p(x)=5 x-4 x^{2}+3$ then $p(-1)=?$

Question.

If $p(x)=5 x-4 x^{2}+3$ then $p(-1)=?$

(a) 2

(b) –2

(c) 6

(d) –6

Solution:

$p(x)=5 x-4 x^{2}+3$

Putting $x=-1$ in $p(x)$, we get

$p(-1)=5 \times(-1)-4 \times(-1)^{2}+3=-5-4+3=-6$

Hence, the correct answer is option (d).