If R is a relation from


If $R$ is a relation from $A=\{11,12,13\}$ to $B=\{8,1012\}$ defined by $y=x-3$, then $R^{-1}=$


Given: $R=\{(x, y): y=x-3, x \in A$ and $y \in B\}$, where $A=\{11,12,13\}$ and $B=\{8,1012\}$.

R = {(11, 8), (13, 10)}

Therefore, $R^{-1}=\{(8,11),(10,13)\}$

Hence, $R^{-1}=\{(\underline{8}, 11),(\underline{10}, 13)\}$.

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