If tan 2 A = cot (A – 18°), where 2 A is an acute angle,
Question.
If tan 2 A = cot (A – 18°), where 2 A is an acute angle, find the value of A.
If tan 2 A = cot (A – 18°), where 2 A is an acute angle, find the value of A.
Solution:
tan2A = cot(A – 18°)
cot (90° – 2A) = cot (A – 18°)
90° – 2A = A – 18°
108° = 3A
A = 36°
tan2A = cot(A – 18°)
cot (90° – 2A) = cot (A – 18°)
90° – 2A = A – 18°
108° = 3A
A = 36°