If the circumference and the area of a circle are numerically equal, then diameter of the circle is
(a) $\frac{\pi}{2}$
(b) $2 \pi$
(c) 2
(d) 4
We have given that circumference and area of a circle are numerically equal.
Let it be x.
Let r be the radius of the circle, therefore, circumference of the circle is and area of the circle will be.
Therefore, from the given condition we have,
$2 \pi r=x$.......(1)
$\pi r^{2}=x \ldots \ldots(2)$
Therefore, from equation (1) get $r=\frac{x}{2 \pi}$. Now we will substitute this value in equation (2) we get, $\pi\left(\frac{x}{2 \pi}\right)^{2}=x$
Simplifying further we get,
$\pi \times \frac{x^{2}}{4 \pi^{2}}=x$
Cancelling x we get,
$\pi \times \frac{x}{4 \pi^{2}}=1$
Now we will cancel
$\frac{x}{4 \pi}=1$...(3)
Now we will multiply both sides of the equation (3) by $4 \pi$ we get, $x=4 \pi$
We can rewrite this equation as given below, $x=2 \times \pi \times 2$
Comparing equation (4) with equation (1) we get $r=2$
Therefore, radius of the circle is 2. We know that diameter of the circle is twice the radius of the circle.
$\therefore$ diameter $=2 \times$ radius
$\therefore$ diameter $=2 \times 2$
$\therefore$ diameter $=4$
Therefore, diameter of the circle is 4 .
Hence, option $(d)$ is correct.