**Question:**

**If the coefficient of performance of a refrigerator is 5 and operates at the room temperature, find the temperature inside the refrigerator.**

**Solution:**

To find the temperature inside the refrigerator, we need to find the work done

W = 0

Q1 = Q2

β = ∞

Where β is the coefficient of performance

Given,

T1 = 27 + 273 = 300 K

Coefficient of performance of refrigerator ω = 5

Coefficient of performance is given as

$\beta=\frac{Q_{2}}{Q_{1}-Q_{2}}$

Using the above equation, the temperature can be determined

$\omega=\frac{T_{2}}{T_{1}-T_{2}}$

T2 = -23oC.