If the distance between the foci of an ellipse is 6 and

Question:

If the distance between the foci of an ellipse is 6 and the distance between its directrices is 12 , then the length of its latus rectum is :

  1. $\sqrt{3}$

  2. $2 \sqrt{3}$

  3. $3 \sqrt{2}$

  4. $\frac{3}{\sqrt{2}}$


Correct Option: , 3

Solution:

Given $2 \mathrm{ae}=6 \Rightarrow \mathrm{ae}=3$ ................(1)

and $\frac{2 a}{e}=12 \Rightarrow a=6 e ...............(2)

from (1) and (2)

$6 \mathrm{e}^{2}=3 \Rightarrow \mathrm{e}=\frac{1}{\sqrt{2}}$

$\Rightarrow a=3 \sqrt{2}$

Now, $b^{2}=a^{2}\left(1-e^{2}\right)$

$\Rightarrow \mathrm{b}^{2}=18\left(1-\frac{1}{2}\right)=9$

Length of L.R $=\frac{2(9)}{3 \sqrt{2}}=3 \sqrt{2}$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now