If the equation x2 − ax + 1 = 0 has two distinct roots, then


If the equation $x^{2}-a x+1=0$ has two distinct roots, then

(a) $|a|=2$

(b) $|a|<2$

(c) $|a|>2$

(d) None of these


The given quadric equation is $x^{2}-a x+1=0$, and roots are distinct.

Then find the value of $a$.

Here, $a=1, b=a$ and,$c=1$

As we know that $D=b^{2}-4 a c$

Putting the value of $a=1, b=a$ and, $c=1$

$=(a)^{2}-4 \times 1 \times 1$


The given equation will have real and distinct roots, if $D>0$




$>\pm 2$

Therefore, the value of $|a|>2$

Thus, the correct answer is (c)

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