If the first term of an A.P. is 3 and the sum of its first

Question:

If the first term of an A.P. is 3 and the sum of its first 25 terms is equal to the sum of its next 15 terms, then the common difference of this A.P. is :

  1. (1) $\frac{1}{6}$

  2. (2) $\frac{1}{5}$

  3. (3) $\frac{1}{4}$

  4. (4) $\frac{1}{7}$


Correct Option: 1

Solution:

Given $a=3$ and $S_{25}=S_{40}-S_{25}$

$\Rightarrow 2 S_{25}=S_{40}$

$\Rightarrow 2 \times \frac{25}{2}[6+24 d]=\frac{40}{2}[6+39 d]$

$\Rightarrow 25[6+24 d]=20[6+39 d]$

$\Rightarrow 5(2+8 d)=4(2+13 d)$

$\Rightarrow 10+40 d=8+52 d$

$\Rightarrow d=\frac{1}{6}$

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