Question: If the lines $\frac{\mathrm{x}-1}{2}=\frac{\mathrm{y}+1}{3}=\frac{\mathrm{z}-1}{4}$ and $\frac{\mathrm{x}-3}{1}=\frac{\mathrm{y}-\mathrm{k}}{2}=\frac{\mathrm{z}}{1}$ intersect, then $\mathrm{k}$ is equal to :
0
$-1$
$\frac{2}{9}$
$\frac{9}{2}$
Correct Option: , 4
Solution: