If the mean of observation x1, x2,


If the mean of observation $x_{1}, x_{2}, \ldots, x_{n}$ is $\bar{x}$, then the mean of $x_{1}+a, x_{2}+a_{1} \ldots \ldots, x_{n}+a$ is

(a) $a \bar{x}$

(b) $\bar{x}-a$

(c) $\bar{x}+a$

(d) $\frac{\bar{x}}{a}$


The mean of $x_{1}, x_{2}, \ldots, x_{n}$ is $\bar{x}$.

$\therefore \frac{x_{1}+x_{2}+x_{3}+\ldots+x_{n}}{n}=\bar{x}$

$\Rightarrow x_{1}+x_{2}+x_{3}+\ldots+x_{n}=n \bar{x}$

Mean of $x_{1}+a_{1} x_{2}+a, \ldots, x_{n}+a$



$=\frac{n \bar{x}+n a}{n}$


Hence, the correct option is (c).


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