If the quadratic equation 2x


If the quadratic equation 2x2 – (a3 + 8a – 1) x + a2 – 4a = 0 possesses roots of opposite signs, then a lies in the interval ____________.


For $2 x^{2}-\left(a^{3}+8 a-1\right) x+a^{2}-4 a=0$ has roots of opposite sign.

Let $\alpha$ and $\beta$ be 2 roots of above equation.

Then, according to give condition,

$\alpha \beta<0$

also, since sum of roots $=\frac{a^{3}+8 a-1}{2}$

$\Rightarrow \alpha+\beta=\frac{a^{3}+8 a-1}{2}$

and product of roots is $a^{2}-4 a$

i. e. $\alpha \beta=a^{2}-4 a$

since $\alpha \beta<0$

$\Rightarrow a^{2}-4 a<0$

i.e. $a(a-4)<0$

Since a(a – 4) < 0 is true for 0 < a < 4

Hence a ∈ (0, 4)

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now