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If the straight line, 2 x-3 y+17=0 is perpendicular to the line passing

Question:

If the straight line, $2 x-3 y+17=0$ is perpendicular to the line passing through the points $(7,17)$ and $(15, \beta)$, then $\beta$ equals :-

  1. $-5$

  2. $-\frac{35}{3}$

  3. $\frac{35}{3}$

  4. 5


Correct Option: , 4

Solution:

$\frac{17-\beta}{-8} \times \frac{2}{3}=-1$

$\beta=5$

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