If the system of linear equations :

Question:

If the system of linear equations :

$x+a y+z=3$

$x+2 y+2 z=6$

$x+5 y+3 z=b$

has no solution, then :-

  1. $\mathrm{a}=-1, \mathrm{~b}=9$

  2. $a \neq-1, b=9$

  3. $\mathrm{a}=1, \mathrm{~b} \neq 9$

  4. $\mathrm{a}=-1, \mathrm{~b} \neq 9$


Correct Option: 1,

Solution:

Solution Not Required

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