# If z=1−cosθ+i sinθ,

Question:

If $z=1-\cos \theta+i \sin \theta$, then $|z|=$

(a) $2 \sin \frac{\theta}{2}$

(b) $2 \cos \frac{\theta}{2}$

(c) $2\left|\sin \frac{\theta}{2}\right|$

(d) $2\left|\cos \frac{\theta}{2}\right|$

Solution:

(c) $2\left|\sin \frac{\theta}{2}\right|$

$\because z=1-\cos \theta+i \sin \theta$

$\Rightarrow|z|=\sqrt{(1-\cos \theta)^{2}+\sin ^{2} \theta}$

$\Rightarrow|z|=\sqrt{1+\cos ^{2} \theta-2 \cos \theta+\sin ^{2} \theta}$

$\Rightarrow|z|=\sqrt{1+1-2 \cos \theta}$

$\Rightarrow|z|=\sqrt{2(1-\cos \theta)}$

$\Rightarrow|z|=\sqrt{4 \sin ^{2} \frac{\theta}{2}}$

$\Rightarrow|z|=2\left|\sin \frac{\theta}{2}\right|$