Question:
In a medical examination of students of a class, the following blood groups are recorded:
From this class, a student is chosen at random. What is the probability that the chosen student has blood group AB?
(a) $\frac{13}{20}$
(b) $\frac{3}{8}$
(C) $\frac{1}{5}$
(d) $\frac{11}{40}$
Solution:
(c) $\frac{1}{5}$
Explanation:
Total number of students = 40
Number of students with blood group AB = 8
Let E be the event that the selected student's blood group is AB.
$\therefore$ Required probability $=P(E)=\frac{8}{40}=\frac{1}{5}$
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