Question:
In a reaction, 2A → Products, the concentration of A decreases from 0.5 mol L−1 to 0.4 mol L−1 in 10 minutes. Calculate the rate during this interval?
Solution:
Average rate $=-\frac{1}{2} \frac{\Delta[\mathrm{A}]}{\Delta t}$
$=-\frac{1}{2} \frac{[\mathrm{A}]_{2}-[\mathrm{A}]_{1}}{t_{2}-t_{1}}$
$=-\frac{1}{2} \frac{0.4-0.5}{10}$
$=-\frac{1}{2} \frac{-0.1}{10}$
= 0.005 mol L−1 min−1
= 5 × 10−3 M min−1
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