In a rectangle ABCD,
Question:
In a rectangle ABCD, prove that ∆ACB ≅ ∆CAD.
Solution:
In ∆ACB and ∆CAD:
AB = CD (rectangle property)
AD = BC (rectangle property)
AC ( common side )
Hence, by SSS criterion, it is proved that ∆ACB ≅ ∆CAD.