In a rectangle ABCD,

Question:

In a rectangle ABCD, prove that ∆ACB ≅ ∆CAD.

Solution:


In ∆ACB and ∆CAD:

 

AB = CD (rectangle property)

 

AD = BC (rectangle property)

 

AC ( common side )

 

Hence, by SSS criterion, it is proved that  ∆ACB ≅ ∆CAD.

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