In a single throw of a die, the probability of getting a multiple of 3 is

Question:

In a single throw of a die, the probability of getting a multiple of 3 is

(a) $\frac{1}{2}$

(b) $\frac{1}{3}$

(c) $\frac{1}{6}$

 

(d) $\frac{2}{3}$

Solution:

GIVEN: A dice is thrown once

TO FIND: Probability of getting a multiple of 3.

Total number on a dice is 6.

Numbers which are on multiple of 3 are 3 and 6

Total number of numbers which are multiple of 3 is 2

We know that PROBABILITY = 

Hence probability of getting a number which are multiple of 3 is equal to 

Hence the correct option is 

 

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