In a single throw of a pair of dice, the probability of getting the sum a perfect square is

Question:

In a single throw of a pair of dice, the probability of getting the sum a perfect square is

(a) $\frac{1}{18}$

(b) $\frac{7}{36}$

(c) $\frac{1}{6}$

(d) $\frac{2}{9}$

 

Solution:

GIVEN: A pair of dice is thrown

TO FIND: Probability of getting the sum a perfect square

Let us first write the all possible events that can occur

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6),

Hence total number of events is 

Favorable events i.e. getting the sum as a perfect square are

(1,3), (2,2), (3,1), (3,6), (4,5), (5,4), (6,3)

Hence total number of favorable events is 7

We know that PROBABILITY = 

Hence probability of getting the sum a perfect square is

Hence the correct option is option 

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