In a single throw of two dice, find


In a single throw of two dice, find P (a total of 10)



We know that,

Probability of occurrence of an event $=\frac{\text { Total no.of Desired outcomes }}{\text { Total no.of outcomes }}$

Total outcomes are $(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)$,






Desired outcomes are $(4,6),(5,5),(6,4)$

Total no. of outcomes are 36 and desired outcomes are 3

Therefore, the probability of getting a total of 10



Conclusion: Probability of getting total sum 10, when two dice are rolled is $\frac{1}{12}$


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