In ∆ABC and ∆DEF, it is given that ∠B = ∠E, ∠F = ∠C and AB = 3DE,


In ∆ABC and ∆DEF, it is given that ∠B = ∠E, ∠F = ∠C and AB = 3DE, then the two triangles are
(a) congruent but not similar
(b) similar but not congruent
(c) neither congruent nor similar
(d) similar as well as congruent


(b) similar but not congruent
In ∆ABC and ∆DEF, we have:

$\angle B=\angle E$ and $\angle F=\angle C$

Applying $A A$ similarity theorem, we conclude that $\triangle A B C \sim \triangle D E F$.


$A B=3 D E$

$\Rightarrow A B \neq D E$

Therefore, $\triangle A B C$ and $\triangle D E F$ are not congruent.


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