In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

3 boys and 3 girls are to be selected from 5 boys and 4 girls.

$\therefore$ Required ways $={ }^{5} C_{3} \times{ }^{4} C_{3}=\frac{5}{3} \times \frac{4}{2} \times \frac{3}{1} \times \frac{4}{3} \times \frac{3}{2} \times \frac{2}{1}=40$