In order to determine the Young's Modulus of a wire of radius 0.2cm (measured using a scale of least count =0.001cm)

$\mathrm{Y}=\frac{\text { Stress }}{\text { Strain }}=\frac{\mathrm{FL}}{\mathrm{Al}}=\frac{\mathrm{mg} \cdot \mathrm{L}}{\pi \mathrm{R}^{2} \cdot \ell}$

$\frac{\Delta \mathrm{Y}}{\mathrm{Y}}=\frac{\Delta \mathrm{m}}{\mathrm{m}}+\frac{\Delta \mathrm{L}}{\mathrm{L}}+2 \cdot \frac{\Delta \mathrm{R}}{\mathrm{R}}+\frac{\Delta \ell}{\ell}$

$\frac{\Delta \mathrm{Y}}{\mathrm{Y}} \times 100=100\left[\frac{1}{1000}+\frac{1}{1000}+2\left(\frac{0.001}{0.2}\right)+\frac{0.001}{0.5}\right]$

$=\frac{1}{10}+\frac{1}{10}+1+\frac{1}{5}=\frac{14}{10}=1.4 \%$