In Q. No. 1, the probability that the digit is a multiple of 3 is

Question:

In Q. No. 1, the probability that the digit is a multiple of 3 is

(a) $\frac{1}{3}$

(b) $\frac{2}{3}$

(c) $\frac{1}{9}$

 

(d) $\frac{2}{9}$

Solution:

GIVEN: digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.

TO FIND: Probability of getting a multiple of 3

Total number of digits is 9

Digits that are multiple of 3 are 3, 6 and 9

Total digits that are multiple of 3 are 3

We know that PROBABILITY = 

Hence probability of getting a multiple of 3 is 

Hence the correct option is option

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