# In Q. No. 1, The probability that the digit is even is

Question:

In Q. No. 1, The probability that the digit is even is

(a) $\frac{4}{9}$

(b) $\frac{5}{9}$

(c) $\frac{1}{9}$

(d) $\frac{2}{3}$

Solution:

GIVEN: digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.

TO FIND: Probability of getting an even digit

Total number of digits is 9

Digits that are even number are 2, 4, 6, and 8

Total number of even digits is 4.

We know that PROBABILITY =

Hence probability of getting an even digit is

Hence the correct option is