In the adjoining figure, three coplanar lines AB, CD and EF intersect at a point O, forming angles as shown. Find the values of x, y, z and t.
We know that if two lines intersect, then the vertically opposite angles are equal.
$\therefore \angle B O D=\angle A O C=90^{\circ}$
Hence, $t=90^{\circ}$
Also,
$\angle D O F=\angle C O E=50^{\circ}$
Hence, $z=50^{\circ}$
Since, AOB is a straight line, we have:
$\angle A O C+\angle C O E+\angle B O E=180^{\circ}$
$\Rightarrow 90+50+y=180^{\circ}$
$\Rightarrow 140+y=180^{\circ}$
$\Rightarrow y=40^{\circ}$
Also,
$\angle B O E=\angle A O F=40^{\circ}$
Hence, $x=40^{\circ}$
$\therefore x=40^{\circ}, y=40^{\circ}, z=50^{\circ}$ and $t=90^{\circ}$
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