In the circuit, given in the figure currents in different branches and value of one resistor are shown.
Question:
In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point $B$ with respect to the point $A$ is :
Correct Option: , 4
Solution:
Let us assume the potential at $A=V_{A}=0$
Using Kirchoff's junction rule at $C$, we get
$i_{1}+i_{3}=i_{2}$
$1 \mathrm{~A}+i_{3}=2 \mathrm{~A} \Rightarrow i_{3}=2 \mathrm{~A}$
Now using Kirchoff's loop law along $A C D B$
$V_{A}+1+i_{3}(2)-2=V_{B}$
$\Rightarrow V_{A}+1+i_{3}(1)-2=V_{B}$
$\Rightarrow V_{B}-V_{A}=3-2=1$ volt
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