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In the expansion of

Question:

In the expansion of $\left(\frac{\mathrm{x}}{\cos \theta}+\frac{1}{\mathrm{x} \sin \theta}\right)^{16}$, if $\ell_{1}$ is

the least value of the term independent of $x$

when $\frac{\pi}{8} \leq \theta \leq \frac{\pi}{4}$ and $\ell_{2}$ is the least value of the term independent of $x$ when $\frac{\pi}{16} \leq \theta \leq \frac{\pi}{8}$, then the ratio $\ell_{2}: \ell_{1}$ is equal to :

  1. $1: 8$

  2. $1: 16$

  3. $8: 1$

  4. $16: 1$


Correct Option: , 4

Solution:

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