Question:
In the figure shown below, the charge on the left plate of the $10 \mu \mathrm{F}$ capacitor is $-30 \mu \mathrm{C}$. The charge on the right plate of the $6 \mu \mathrm{F}$ capacitor is :
Correct Option: , 4
Solution:
As given in the figure, $6 \mu \mathrm{F}$ and $4 \mu \mathrm{F}$ are in parallel. Now using charge conservation\
Charge on $6 \mu \mathrm{F}$ capacitor $=\frac{6}{6+4} \times 30$
$=18 \mu \mathrm{C}$
Since charge is asked on right plate therefore is $+18 \mu \mathrm{C}$
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