Question:
In the following sequence of reactions a compound
$\mathbf{A}$, (molecular formula $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}$ ) with a straight chain structure gives a $\mathrm{C}_{4}$ carboxylic acid. $\mathbf{A}$ is :
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{COO}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{COO}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{OH}$
Correct Option: , 3
Solution:
