In the given figure, a body of mass $M$ is held between two massless springs, on a smooth inclined plane.
Question:
In the given figure, a body of mass $M$ is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant $\mathrm{k}$, the frequency of oscillation of given body is :
Correct Option: 1
Solution:
(1)
Equivalent $\mathrm{K}=\mathrm{K}+\mathrm{K}=2 \mathrm{~K}$
Now, $\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{K}_{\mathrm{mq}}}}$
$\Rightarrow \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{m}}{2 \mathrm{k}}}$
$\therefore \mathrm{f}=\frac{1}{2 \pi} \sqrt{\frac{2 \mathrm{k}}{\mathrm{m}}}$
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