In the given figure ABCD is a quadrilateral in which diagonal BD = 64 cm,


In the given figure ABCD is a quadrilateral in which diagonal BD = 64 cm, AL ⊥ BD and CM ⊥ BD such that AL = 16.8 cm and CM = 13.2 cm. Calculate the area of quadrilateral ABCD.



Area of $A B C D=$ Area of $\triangle A B D+$ Area of $\triangle B D C$

$=\frac{1}{2} \times B D \times A L+\frac{1}{2} \times B D \times C M$

$=\frac{1}{2} \times B D(A L+C M)$

$=\frac{1}{2} \times 64(16.8+13.2)$

$=32 \times 30$

$=960 \mathrm{~cm}^{2}$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now