In the given figure, l || m and a transversal t cuts them. If ∠1 = 120°, find the measure of each of the remaining marked angles.
We have, $\angle 1=120^{\circ}$. Then,
$\angle 1=\angle 5$ [Corresponding angles]
$\Rightarrow \angle 5=120^{\circ}$
$\angle 1=\angle 3$ [Vertically-opposite angles]
$\Rightarrow \angle 3=120^{\circ}$
$\angle 5=\angle 7$ [Vertically-opposite angles]
$\Rightarrow \angle 7=120^{\circ}$
$\angle 1+\angle 2=180^{\circ}$ [Since AFB is a straight line]
$\Rightarrow 120^{\circ}+\angle 2=180^{\circ}$
$\Rightarrow \angle 2=60^{\circ}$
$\angle 2=\angle 4$ [Vertically-opposite angles]
$\Rightarrow \angle 4=60^{\circ}$
$\angle 2=\angle 6$ [Corresponding angles]
$\Rightarrow \angle 6=60^{\circ}$
$\angle 6=\angle 8$ [Vertically-opposite angles]
$\Rightarrow \angle 8=60^{\circ}$
$\therefore \angle 1=120^{\circ}, \angle 2=60^{\circ}, \angle 3=120^{\circ}, \angle 4=60^{\circ}, \angle 5=120^{\circ}$,
$\angle 6=60^{\circ}, \angle 7=120^{\circ}$ and $\angle 8=60^{\circ}$
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