Question:
In the given figure, LM CB and LN CD.
Prove that $\frac{A M}{A B}=\frac{A N}{A D}$.
Solution:
$L M \| C B$ and $L N \| C D$
Therefore, applying Thales' theorem, we have:
$\frac{A B}{A M}=\frac{A C}{A L}$ and $\frac{A D}{A N}=\frac{A C}{A L}$
$\Rightarrow \frac{A B}{A M}=\frac{A D}{A N}$
$\therefore \frac{A M}{A B}=\frac{A N}{A D}$
This completes the proof.
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