In the given figure, O is the centre of the circle.

Question:

In the given figure, O is the centre of the circle. If ABD = 35° and ∠BAC = 70°, find ∠ACB.

 

Solution:

It is clear that BD is the diameter of the circle.
Also, we know that the angle in a semicircle is a right angle.
i.e., BAD = 90°
Now, considering the ΔBAD, we have:
ADB + BAD + ABD = 180°  (Angle sum property of a triangle)
⇒ ADB + 90° + 35° = 180°
⇒ ADB = (180° - 125°) = 55°
Angles in the same segment of a circle are equal.
Hence, ACB = ADB = 55°

 

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now