In the ring test of NO3– ion,

Question:

In the ring test of NO3– ion, Fe2+ ion reduces nitrate ion to nitric oxide, which combines with Fe2+ (aq) ion to form the brown complex. Write the reactions involved in the formation of a brown ring.

Solution:

NO3 + 3Fe2+ + 4H+ → NO + 3Fe2+ 2H2O

[Fe(H2O)6]SO4 + NO → [Fe(H2O)5NO]SO4

 

Thus the complex formed is brown.

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