Ionisation energy of

Question:

Ionisation energy of $\mathrm{He}^{+}$is $19.6 \times 10^{-18} \mathrm{~J}_{\text {atom }^{-1}}$. The energy of the first stationary state $(\mathrm{n}=1)$

  1. $8.82 \times 10^{-17} \mathrm{~J}$ atom $^{-1}$

  2. $4.41 \times 10^{-16} \mathrm{~J}_{\text {atom }}-1$

  3. $-4.41 \times 10^{-17} \mathrm{~J}_{\text {atom }^{-1}}$

  4. $-2.2 \times 10^{-15} \mathrm{~J}$ atom ${ }^{-1}$

Correct Option: , 3

Solution:

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