It is given that ∆ABC ≅ ∆ FDE in which AB = 5 cm, ∠B = 40°, ∠A = 80°

Question:

It is given that ABC ≅ ∆ FDE in which AB = 5 cm, ∠B = 40°, A = 80° and FD = 5 cm. Then, which of the following is true?
(a) ∠D = 60°
(b) ∠E = 60°

(c) ∠F = 60°
(d) D = 80°

Solution:

(b) $\angle E=60^{\circ}$

$\Delta A B C \cong \Delta F D E$

$\mathrm{AB}=5 \mathrm{~cm}, \angle B=40^{\circ}, \angle A=80^{\circ}$ and $\mathrm{FD}=5 \mathrm{~cm}$

Then $\angle A+\angle B+\angle C=180^{\circ}$

$\Rightarrow 80^{\circ}+40^{\circ}+\angle C=180^{\circ}$

$\Rightarrow \angle C=60^{\circ}$

Also, $\angle C=\angle E$

$\therefore \angle E=60^{\circ}$

 

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now