**Question:**

It is known that a box of 800 electric bulbs contains 36 defective bulbs.One bulb is taken at random out of the box. What is the probability that the bulb chosen is non-defective?

**Solution:**

Total number of electric bulbs in the box = 800

Number of defective electric bulbs in the box = 36

∴ Number of non-defective electric bulbs in the box = 800 − 36 = 764

$P($ Bulb chosen is non-defective $)=\frac{\text { Number of non defective electric bulbs in the box }}{\text { Total number of electric bulbs in the box }}=\frac{764}{800}=\frac{191}{200}$

Thus, the probability that the bulb chosen is non-defective is $\frac{191}{200}$.

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