Let f :


Let $f:\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \rightarrow A$ be defined by $f(x)=\sin x$. If $f$ is a bijection, write set $A$.


$\because f$ is a bijection,

co-domain of $f=$ range of $f$

As $-1 \leq \sin x \leq 1$

$-1 \leq y \leq 1$

So, $A=[-1,1]$

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