Question:
Let $f: R \rightarrow R, g: R \rightarrow R$ be two functions defined by $f(x)=x^{2}+x+1$ and $g(x)=1-x^{2}$. Write fog $(-2)$.
Solution:
$(f o g)(-2)=f(g(-2))$
$=f\left(1-(-2)^{2}\right)$
$=f(-3)$
$=(-3)^{2}+(-3)+1$
$=9-3+1$
$=7$
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