Let F1 (A,B,C) =


Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F_{2}(A, B)=(A \vee B) \vee(B \rightarrow \sim A)$ be two logical expressions.


  1. (1) $\mathrm{F}_{1}$ is not a tautology but $\mathrm{F}_{2}$ is a tautology

  2. (2) $\mathrm{F}_{1}$ is a tautology but $\mathrm{F}_{2}$ is not a tautology

  3. (3) $\mathrm{F}_{1}$ and $\mathrm{F}_{2}$ both area tautologies

  4. (4) Both $\mathrm{F}_{1}$ and $\mathrm{F}_{2}$ are not tautologies

Correct Option: 1


Truth table for $\mathrm{F}_{1}$

Not a tautology

Truth table for $\mathrm{F}_{2}$

$\mathrm{F}_{1}$ not shows tautology and $\mathrm{F}_{2}$ shows tautology

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