Question:
Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F_{2}(A, B)=(A \vee B) \vee(B \rightarrow \sim A)$ be two logical expressions.
Then:
Correct Option: 1
Solution:
Truth table for $\mathrm{F}_{1}$
Not a tautology
Truth table for $\mathrm{F}_{2}$
$\mathrm{F}_{1}$ not shows tautology and $\mathrm{F}_{2}$ shows tautology
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