# Let P be a plane passing through the points

Question:

Let $P$ be a plane passing through the points $(2,1,0)$, $(4,1,1)$ and $(5,0,1)$ and $R$ be any point $(2,1,6)$. Then the image of $R$ in the plane $P$ is:

1. $(6,5,2)$

2. $(6,5,-2)$

3. $(4,3,2)$

4. $(3,4,-2)$

Correct Option: , 2

Solution:

Equation of plane is $x+y-2 z=3$

$\Rightarrow \frac{x-2}{1}=\frac{y-1}{1}=\frac{z-6}{-2}=\frac{-2(2+1-12-3)}{6}$

$\Rightarrow \quad(x, y, z)=(6,5,-2)$